Question

if a^x=b , b^y=c , c^z=a
show that xyz=1( abc positive numbers)

Answer 1

a ^xyz = a
so xyz = 1

Answer 2

x=logb/loga y=logc/logb z=loga/logc

Answer 3

xyz= logb/loga x logc/logb x loga/logc =1

Answer 4

how a^xyz=1

Answer 5

x/(b+c-a) = z/(a+b-c) => (a+b-c)x = (b+c-a)z
x/(b+c-a) = y/(c+a-b) => (c+a-b)x = (b+c-a)y
So (b+c-a)(z-y) = 2(b-c)x

Answer 6

a^x=b and b^y = c
therefore a^xy = c
a^xy = c and c^z = a
therefore a^xyz = a
now a^1 = a
therefore xyz = 1

Answer 7

thamkz a lot.i got it..

Answer 8

good

Answer 9

2^2^x=16^263x
solve