Question

using Pythagorean theorem find b if a=10 and c=16

Answer 1

a^2+b^2=c^2


a^2+10^2=16^2


a^2+100=256


a^2=256-100


a^2=156


a=sqrt(156)


a = 2*sqrt(39)

Answer 2

i know 10^2=100 and 16^2=256 but 256-100=156 which does not have a perfect square

Answer 3

oh I swapped a and b, but it's all the same, so b = 2*sqrt(39)

Answer 4

b^2+100=256, b^2=156, b=sqrt156

Answer 5

b^2=10^+16^2
=356
b=2sqrt89 (by squaring both sides)

Answer 6

so the answer is \[2\sqrt{39}\]

Answer 7

exactly

Answer 8

i am confused on how answer is 2 sqrt 39

Answer 9

they pulled out a 4 since 4*39=156 4is a perfect square so 2sqrt39

Answer 10

\[b^2=\sqrt{16^2-10^2}=\sqrt{256-100}=\sqrt{156}=\sqrt{4\times 39}=\sqrt{4}\times \sqrt{39}=2\sqrt{39}\]

Answer 11

\[\large \sqrt{156}=\sqrt{4*39}=\sqrt{4}\sqrt{39}=2\sqrt{39}\]
So \[\large \sqrt{156}=2\sqrt{39}\]

Answer 12

@jenni, what u want to know?
clearify

Answer 13

what b would equal if a=10^2 and c=16^2 using the Pythagorean theorem

Answer 14

b would be 2sqrt39 if simplified

Answer 15

a=10, c=16, b=?
a^2+b^2=c^2
a^2=10^2=100 and c^2=16^2=256

b^2=c^2-a^2=256-100=156
b=sqrt[156]=sqrt[4*39]=sqrt[4]*sqrt[39]=2*sqrt[39]