Question

x^2+6x=5

Answer 1

Was their a particular method they wanted you to use?

Answer 2

sorry, the quad. formula (discriminant)

Answer 3

to solve this use the quadratic formula
x = (-b +- sqrt(b^2-4ac)) / 2a
or complete the square

Answer 4

\[b ^{2}-4ac=36+20=56\] or positive value non perfect square that means Two distinct irrational answers

Answer 5

Do you want further guidance in using the Quadratic Formula?

Answer 6

yes please

Answer 7

What I used above was the discriminate to test what kind of answers was expected.

Answer 8

Step 1. Put your equation into standard form which is \[Ax ^{2}+Bx + C=0\]\[x ^{2}+6x-5=0\]We see that A=1, B=6, and C=-5
Are you with me so far?

Answer 9

yes

Answer 10

Step 2. Get the quadratic formula (if you do not have it memorized). Here it is:\[-B \pm \sqrt{B ^{2}-4(A)(C)}\over2A\]
Step 3. Plug in the numbers getting\[-6\pm \sqrt{36+4\times 1\times 5}\over2\] Please note since C was a -5, that the second term in the radical became positive.
Still with me?

Answer 11

yes

Answer 12

Now it is just like arithmetic:\[-6\pm \sqrt{56}\over2\] The square root of 56 can be simplified as\[\sqrt{56}=\sqrt{14}\sqrt{4}=2\sqrt{14}\]Now we have:\[6\pm2\sqrt{14}\over2\] do the division getting:\[3\pm \sqrt{14}\] That is the answer:
\[3+\sqrt{14}\]\[3-\sqrt{14}\]

Answer 13

If you have to get decimal answers use your calculator, but most teachers accept it in the form above.

Answer 14

ok thank u

Answer 15

you're welcome and good luck with those problems.