the question says to solve the inequalities algebraically. here's the one I don't understand:
I'm given the equation y=3x/x-2, and the inequality i'm given to plug into the equation is y>6 (also equal to, just can't type it on the computer) The back of the book says the answer is 2
i get x > 4...
3x>6x-12
-3x>12 when you divide by a - you must inverse the inequality x<4
yea i did it backwards...i multiplied teh (x-2) out and distributed it with the 6 to get 6x-12> 3x
my bad
how do you get -3x>12? I get 12<or equal to 3x.
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so sloppy hahaha
it's okay. When I distribute that, I get 3x<6x-12. then what?
move the x's to one side
your inequality is not right look at my picture
so that it's one expression
sorry. just flipped the sign.when i move the x's to one side, I get -3x>-12. I then divide by -3, which gives me x<4, right?
The answer in the back of the book says 2<x<4
so that's half of it....
cant have denomenator <0 so if its x-2 then x must be >2
OOOHHHHH. that makes sense. and sounds something like what my teacher said in class. thanks so much. : )
well...think of it like this....u can't divide by 0...yet..wait til calculus
what number in x-2 would = 0?
AP calculus is next year. don't remind me.
2 - 2 is 0.....so you can't have 2 as an answer
calculus isn't hard...don't let ppl scare you
yep. 2. can't be 0.
so you have to include that in your inequality
i did. thanks everyone for the awesome help!! i think all of you got a medal....even though i'm not really sure what it does. it just sounds good. = )
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