Question

v^2-9 /16v+48 divided by v-3 / 12 =

Answer 1

Some things to note:

v^2-9=v^2-3^2=(v-3)(v+3)

and
16v+48=16(v+3)

Also, note that when you have a fraction divided by a fraction, you can rewrite it as a the top fraction multiplied by the reciprocal of the bottom fraction :
\[\frac{(\frac{a}{b})}{(\frac{c}{d})}=\frac{a}{b}*\frac{d}{c}\]

Answer 2

would you like to try solving it ?

Answer 3

Yes, please

Answer 4

Are you familiar with everything I posted in the notes above ?

Answer 5

I believe so

Answer 6

\[\frac{\frac{v^2-9}{16v+48}}{\frac{v-3}{12}}=\frac{v^2-9}{16v+48}*\frac{12}{v-3}\]

Answer 7

Is the above clear ?

Answer 8

\[=\frac{(v-3)(v+3)}{16(v+3)}*\frac{12}{v-3}=\frac{3*4*(v-3)(v+3)}{4*4*(v-3)(v+3)}=\frac{3}{4}\]