can someone please help me understand this problem.
sqareroot 7a +6 squareroot 175a^3
Any and help help would be greatly appreciated

Question

anonymous · Answer

$$\sqrt{7a}+\sqrt[6]{175a^3}$$

anonymous · Answer

ok you are not allowed do have common factors for powers in "radicand" and "index"

anonymous · Answer

here the "index" is 6, the sixth root.  and you have an exponent of 3.  
$$a^3$$
you also have an power 2 because 
$$175=5^2\times 7$$ hmm you don't get much out of this, but you do get 
$$\sqrt[6]{a^3}=\sqrt{a}$$ and 
$$\sqrt[6]{175}=\sqrt[3]{5}\sqrt[6]{7}$$

anonymous · Answer

oh maybe you are supposed to go backwards? now i am confused.  are you supposed to some how add these?  because i don't think that you can

anonymous · Answer

it says to add. and to simplify

anonymous · Answer

you cannot add because they are not like terms

anonymous · Answer

you are sure it is 175 rigth?  because that is a problem