Question

write as an equivalent radical expression
(3x)^-1/3

Answer 1

\[\sqrt[3]{3x}\]

Answer 2

Sorry, slight mistake...

Answer 3

\[\large (3x)^{-\frac{1}{3}}=\frac{1}{(3x)^{\frac{1}{3}}}=\frac{1}{\sqrt[3]{3x}}\]
So \[\large (3x)^{-\frac{1}{3}}=\frac{1}{\sqrt[3]{3x}}\]

Answer 4

Yes, that was the mistake. Forgot to carry out the inverse operation before inserting the radical