Question

What does it mean by find all real values of x such that f(x) = 0?

I don't really know how to apply that to this problem
f(x)=12- (x^2) / 5

Answer 1

it means set it equal to zero and solve

Answer 2

graph it. Then look at where x = 0. then use your finger and drag it to the graph to see the Y values

Answer 3

?

Answer 4

that's what I would do :D

Answer 5

is it
\[f(x)=12-\frac{x^2}{5}\]?

Answer 6

noo 12 is with -x^2 sorry if I made it unreadable

Answer 7

i got x^2=7

Answer 8

or would it be sqrt +- 7?

Answer 9

so \[\frac{12-x^2}{5}\]

Answer 10

yes

Answer 11

then
\[x=\pm\sqrt{12}=\pm 2\sqrt{3}\]

Answer 12

Wait, what happened to the 5?

Answer 13

you multiply through by 5

Answer 14

so you get 60-5x^2 = 0

Answer 15

a fraction is zero means the numerator is 0 you can ignore the 5

Answer 16

\[\frac{x-2}{72}=0\] same as
\[x-2=0\]

Answer 17

ok wait, it says f(x) equals zero
So why wouldn't it be just 12/5

Answer 18

hold on

Answer 19

it say
\[f(x)=0\] right, and you function is
\[f(x)=\frac{12-x^2}{5}\]

Answer 20

find all real values

Answer 21

it is not asking for
\[f(0)\] it is saying that
\[f(x)=0\]

Answer 22

you confused the two.
\[f(0)=\frac{12-0^2}{5}=\frac{12}{5}\]

Answer 23

but it is not saying that the input is zero. it is saying that the output is 0

Answer 24

\[f(x)=0=\frac{12-x^2}{5}\]

Answer 25

ok , so since its equal to zero you can ignore the denominator?

Answer 26

yes because it is a number

Answer 27

So, if it said to solve for x you would do the same correct?