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Mathematics 21 Online
OpenStudy (anonymous):

find all the zeros of this equation f(x) = 3x^3-7x^2+6x-8 please show work.

OpenStudy (anonymous):

best bet is to factor by grouping

OpenStudy (anonymous):

(3x^3-7x^2)+(6x-8), it is a start

OpenStudy (anonymous):

oh okay. I guess that's all I really needed to know.

OpenStudy (anonymous):

Finding zeros is a pain. First find the possible rational zeros, then test them to see if one will turn up a zero

OpenStudy (anonymous):

this is real and non real though. The idea is to find 3 zeros so that we understand that the degree usually determines the # of zeros

OpenStudy (anonymous):

For this equation: \[3x ^{3}-7x ^{2}+6x-8\] p= \[\pm1,\pm2,\pm4,\pm8\]q=\[\pm1,\pm2\] these are the possible zeros then do p/q, make a chart and plug the p/q values in.

OpenStudy (anonymous):

thank you :)

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