Question

can some one help me with finding the area between curve and lines: y=x, x=2, y=x^(1/x^2) and the x axis in the first quadrent.

Answer 1

correction: can some one help me with finding the area between curve and lines: y=x, x=2, y=1/x^2and the x axis in the first quadrent.

Answer 2

http://www.wolframalpha.com/input/?i=plot {+1%2Fx^2%2C+x}%2C+x%3D0..3%2C+y%3D0..3


If u look at the graph, u can see it is the triangle in the corner plus the area under the curve between 1 and 2.

Answer 3

http://www.wolframalpha.com/input/?i=plot+1%2Fx^2%2C+x%2C+x%3D0..3%2C+y%3D0..3

Didn't like the braces

Answer 4

so then i would have to find the area of the triangle and the area of the rest, then add them together

Answer 5

Yes, which is rather easier than going through the usual rigamarole since the area for triangle is just a 1/2.

Answer 6

now could i use, the integral from 0 to b of x dx=b^2/2 to find the area of the rectangel

Answer 7

i mean to find the area of the triangle

Answer 8

Why would u want to do that?

Answer 9

It's just 1/2*1*1 (half base*height)

Answer 10

oh i was thinking that was the general integration to find the area of a traingle, but now that i am looking it think that is for a trapazoid

Answer 11

All u need now is to integrate your function between 1 and 2 and add a half to the result.

Answer 12

how would i integerate that?

Answer 13

would that just be like, integral from 1 to 2 of 1/x^2

Answer 14

?

Answer 15

would that just be like, integral from 1 to 2 of 1/x^2

That's what I thought I said...:-)

Answer 16

well, you didnt say 1/x^2, but thanks my friend for you help

Answer 17

ur welcome.