Question

(1/2)log[(3)(c^2-d^2)-log(3)(c-d)]
write as single logarithm

Answer 1

man you never quit do you?

Answer 2

forget the base, it is unimportant so it just says "write as a single log"

Answer 3

sry to bother, you don't need to help me if you don't want to

Answer 4

first use
\[\log(A)-\log(B)=\log(\frac{A}{B})\]

Answer 5

i am just teasing. late at night and back by noon!

Answer 6

yeah, I just want this to be over and I feel like an old dog now that can't learn new tricks

Answer 7

so you get
\[\log(\frac{c^2-d^2}{c-d})\]

Answer 8

then factor and cancel on the inside of the log to get
\[\frac{c^2-d^2}{c-d}=\frac{(c+d)(c-d)}{c-d}=c+d\]

Answer 9

giving you
\[\frac{1}{2}\log(c+d)\]

Answer 10

can I ask, are you a math teacher? or you're just always here because you are good and it's enjoyable for you?

Answer 11

now use that
\[n\log(x)=\log(x^n)\] to get
\[\frac{1}{2}\log(c+d)=\log((c+d)^{\frac{1}{2}})=\log(\sqrt{c+d})\]\]

Answer 12

as for your question, i hate to see people have to struggle through questions like this with essentially no content and no meaning, and especially no understanding. it is just a bunch of ruled combined with some algebra rules
http://www.unc.edu/depts/jomc/academics/dri/idog.html

Answer 13

that's awesome. I want to spend time helping people on the writing part of this site, but there aren't nearly as many needing help!