Question

n-1P2=n+1P3?

Answer 1

\[n-1^{P}2\] = \[n+1^{P}3\] I think it looks more like that in the problem

Answer 2

It says in the problem to "solve for n". how's that work?

Answer 3

can you explain what 1P2 and 1P3 mean ?

Answer 4

1 P 2 doesnt look doable if its the notation im thinking of

Answer 5

Solve simple counting problems.
Use the Fundamental Counting Principle to solve counting problems.
Use permutations to solve counting problems.
Use combinations to solve counting problems.

The lesson I'm working on deals with those things, and this was a question in an exam related to that lesson.

Answer 6

nPr only works if r <= n

Answer 7

5P3 means 5.4.3

1P2 means ??? 1.?

1P3 means 1.?.? ... doesnt make sense

Answer 8

and if you solve for n, you prolly get a contradiction since n-n = 0 and your left with the P parts

Answer 9

i don't get it either, hence why i posted it on here.
i've seen permutation with nPr using numbers like 8P2 or something like that, but never n-1P2???

Answer 10

maybe it means
(n-1)P2 ?

Answer 11

P(n-1, 2) = P(n+1,3) might be better

Answer 12

fiddle got it

Answer 13

it would look like n-1!/((n-1)-2)!(2!))

Answer 14

yeah i think fiddle's right

Answer 15

(n-1)*(n-2) = (n+1)*(n+1-1)*(n+1-2)

Answer 16

the answers are n=8; n=4,7; n=3,8; n=3; or no solution (it's multiple choice)

Answer 17

solve this :)

Answer 18

n=1 in that equation according to www.wolframalpha.com

Answer 19

(n-1)*(n-2) = (n+1)*(n+1-1)*(n+1-2)

(n-1)*(n-2) = (n+1)*(n+0)*(n-1)

(n-2) = (n+1)*(n+0)

n - 2 = n^2 +n

- 2 = n^2

no answer?

Answer 20

i'll answer no solution i think; it doesn't seem right

Answer 21

woops, got it wrong, it said the answer was n=3,8

oh well :(

Answer 22

hmm ... mighta back tracked it to dbl chk :)

Answer 23

wolf says 1

Answer 24

yeah. they don't even have any examples related to that problem in my math book. not very helpful

Answer 25

well, thanks for helping guys! it seems my math teacher wants me to fail no matter what! lol

Answer 26

good luck :)