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Can someone please help solve this differential equation: dy/dx=[x(y^2-1)]/[2(x-2)(x-1)]
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Looks separable.
yup
\[\implies \frac{1}{y^2 - 1}\, dy = \frac{x}{2(x-2)(x-1)}\,dx\]
I've gotten it that far, it's the integrals at that point that I'm having trouble with :/
Yeah, they don't look particularly fun, but doable. The first one looks like a trig or hyperbolic trig function.
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For the second, I'd look for a partial fraction decomposition.
thanks so much! i'll try that!
lhs = -tanh x
is the right hand side ln(x-2)-(ln(x-1)/2)?
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