Question

Checking math:

Answer 1

\[\frac{3y^{2} - 6y}{3y^{2} - 15y}\]

\[\frac{3 - 6}{3 - 15}\]

= \[-\frac{3}{12}\] is the final answer I came up with. Because the variables cancel each other out.

Answer 2

Or, did I do this wrong and I should FOIL? I'm going to try that while I wait a reply.

Answer 3

(y-3) / (y-5)

Factor 3y from both denominator and numerator. You get 3y(y-3) / 3y(y-5)

Answer 4

Yeah, thats what I was thinking. Alright.

Answer 5

But wait, how would I get 3y(y-3) for the numerator? Wouldn't that distrubite to be 3y^2 - 9y instead of 6y?

Answer 6

Wouldn't it be 3y(y-2) / 3y(y-5) ?

Answer 7

You cancel the 3y s

Answer 8

and yes upper part should be y-2 not y-3

Answer 9

Alright, thats all I needed to know. Thankis for the help :)

Answer 10

no probs