A committee of three women and seven men is to be seated at a round table .

(a) what is the probability that the three females will sit together?

(b) The committee elects a president and a vice-president. What is the probability that they are sitting opposite one another?

Question

A committee of three women and seven men is to be seated at a round table .

(a) what is the probability that the three females will sit together?

(b) The committee elects a president and a vice-president. What is the probability that they are sitting opposite one another?

amistre64 · Answer

hmm ..... have to think circular rather than linear

anonymous · Answer

yeah it confuses me

anonymous · Answer

n!/n = (n-1)!

anonymous · Answer

thats for circular problems

amistre64 · Answer

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amistre64 · Answer

i havent done n! for circles to be confident :)

anonymous · Answer

the total will be:

(10-1)!=9! = 362880

amistre64 · Answer

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amistre64 · Answer

and id say 10 ways for them to be seated next to each other

amistre64 · Answer

do we count the other way too?  or just keep it in the same rotation?

anonymous · Answer

no just the same rotation i believe