if sec theta = x + 1/x , prove that sec theta * tan theta = 2x
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OpenStudy (anonymous):
|dw:1314885691162:dw|
OpenStudy (anonymous):
draw a triangle, label hypotenuse
\[x+\frac{1}{x}\] and "adjacent side"1, so that
\[\sec(\theta)=1+\frac{1}{x}\] then solve for the other side using pythagoras and take ratio. i didn't actually do it so let me write it on paper first, but i am fairly certain the solution will pop out
OpenStudy (anonymous):
ok..
OpenStudy (anonymous):
before i make fool of myself, is it
\[x+\frac{1}{x}\] or
\[\frac{x+1}{x}\]?
OpenStudy (anonymous):
can i have the whole answer please??
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OpenStudy (anonymous):
x + 1/x
OpenStudy (anonymous):
first one or second one?
OpenStudy (anonymous):
first one
OpenStudy (aravindg):
help meeeeeee
OpenStudy (anonymous):
plz wait aravind
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OpenStudy (anonymous):
help me first
OpenStudy (anonymous):
i am afraid i do not get 2x
OpenStudy (anonymous):
wat do u get
OpenStudy (anonymous):
in fact i can easily check that it is wrong by picking a value of x
OpenStudy (anonymous):
i'll get back to you. will try working it out. thank you
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OpenStudy (aravindg):
helppppppppppp
OpenStudy (anonymous):
pick x = 1, then x+1/x=1+1=0 and if
\[\sec(\theta)=2\]
\[\cos(\theta)=\frac{1}{2}\] and so
\[\sin(\theta)=\frac{\sqrt{3}}{2}\] and
\[\tan(\theta)=\sqrt{3}\] and finally
\[\sec(\theta)\tan(\theta)=2\times \sqrt{3}\neq 2\times 1\] so it is false