find: f''(x) , when f(x) = $2e^x-3sin(x)+2x\cfrac{1-e^x)}{pi}-2$

Question

amistre64 · Answer

ack.. i left a " ) " hanging in there

angela210793 · Answer

how come ur asking the others? O.o

amistre64 · Answer

becasue it breaks up the algebra blahdom

amistre64 · Answer

i should have asked to go from the f'' to f with conditions of f(0) = f(pi) = 0

amistre64 · Answer

$$f''(x)=2e^x +3sin(x)$$
was the original ; given that f(0) = f(pi) = 0

amistre64 · Answer

and that is what i came up with :)

angela210793 · Answer

ahhhhaaaaa..well let me think

amistre64 · Answer

gotta get for a few, class starting.  Have fun with it and ill check on yall later

angela210793 · Answer

kk,see ya :D

angela210793 · Answer

My opinion(not sure it is right though) u have to integrate to find f'(x) which is 
2e^x-3cosx+c 
then integrate 2e^x-3cosx+c  and u'll get cx+2e^x-3sinx+c
then find c since u have f(0)

anonymous · Answer

I am Getting $f"(x) = 2e^x - \frac{e^x}{\pi} +3sinx$

zarkon · Answer

$$f(x)=2e^x-3\sin(x)+2x\cfrac{1-e^\pi}{\pi}-2$$

zarkon · Answer

$$e^\pi\text{ not }e^x$$ for the second 'e' in the function

anonymous · Answer

ah Lol sorry I am wrong

angela210793 · Answer

how did u guys get tht?

anonymous · Answer

yea you got me... Thanks @Zarkon

anonymous · Answer

hi
$$\cos 30$$

amistre64 · Answer

yeah, i got that right on the paper but wrong on the latex :)  e^pi thnx zarkon