Question

\[x-\sqrt[4]{x} \div x-1\]

Answer 1

need to simplify

Answer 2

\[\frac{x-x^{1/4}}{x-1}\]

Answer 3

yes now to simplify

Answer 4

add 0 :)

Answer 5

can't be simplify further:
http://www.wolframalpha.com/input/?i=(x-x^(1%2F4))%2F(x-1)&t=crmtb01

Answer 6

to find lim
>1

Answer 7

\[1-\cfrac{1}{4}x^{-3/4}\]
id say its 3/4

Answer 8

im right yay!!

http://www.wolframalpha.com/input/?i=limit%28x+to+1%29+%28x-x^%281%2F4%29%29%2F%28x-1%29

Answer 9

you are correct thx

Answer 10

L'Hopitals rule for indeterminate forms

Answer 11

do you want a non L'hospital way?

Answer 12

kk

Answer 13

\[Let u=x^4\]
as x->1, u->1
\[u=x^\frac{1}{4} =>u^4=x\]
so we have
\[\lim_{u \rightarrow 1}\frac{u^4-u}{u^4-1}=\lim_{x \rightarrow 1}\frac{u(u^3-1)}{(u^2-1)(u^2+1)}\]
\[=\lim_{u \rightarrow 1}\frac{u(u-1)(u^2+u+1)}{(u-1)(u+1)(u^2+1)}=\lim_{u \rightarrow 1}\frac{u(u^2+u+1)}{(u+1)(u^2+1)}\]

Answer 14

\[=\frac{1(1^2+1+1)}{(1+1)(1^2+1)}=\frac{1(3)}{2(2)}=\frac{3}{4}\]

Answer 15

thx

Answer 16

np