Question

does anyone know how to do this ???
factor the expression
assume n>0.

81-16y^4n

Answer 1

difference of two squares
\[a^2-b^2=(a+b)(a-b)\] and here
\[a=9,b=4y^{2n}\]

Answer 2

you get
\[(9-4y^{2n})(9+4y^{2n})\][ now repeat with first factor

Answer 3

\[(3-2y^n)(3+2y^n)(9-4y^{2n})\]

Answer 4

so is that my answer? ^

Answer 5

nvm

Answer 6

\[(9+4y ^2)(3-2y)(3+2y)\]
i'm not sure my ans is rite :P

Answer 7

yes i wrote the answer

Answer 8

no, ur ans is wrong