Question

The surface area of a right square pyramid is s=b(sqrt of (b^2+4h^2). If the pyramid has a ht of 10 ft and a surface area of 100 sq feet what is the length of a side b of it's base?

Answer 1

\[s=b \sqrt{b^{2}+4h ^{2}}\] this is a better version of the equation

Answer 2

I just can't figure out how to break down the equation so I can solve it.

Answer 3

anyone? I got the answer which is 4.86 ft but I just filled in answers until I got it. Can someone please show me how to break down this equation to solve for b?