The surface area of a right square pyramid is s=b(sqrt of (b^2+4h^2). If the pyramid has a ht of 10 ft and a surface area of 100 sq feet what is the length of a side b of it's base?

Question

The surface area of a right square pyramid is s=b(sqrt of (b^2+4h^2).  If the pyramid has a ht of 10 ft and a surface area of 100 sq feet what is the length of a side b of it's base?

anonymous · Answer

$$s=b \sqrt{b^{2}+4h ^{2}}$$ this is a better version of the equation

anonymous · Answer

I just can't figure out how to break down the equation so I can solve it.

anonymous · Answer

anyone?  I got the answer which is 4.86 ft but I just filled in answers until I got it.  Can someone please show me how to break down this equation to solve for b?

anonymous · Answer

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