A spherical balloon is inflated with a gas at the rate of 500 cm3/min. How fast is the radius of the balloon increasing at the instant the radius is 30 cm?

Question

anonymous · Answer

Here are my possible answer:
5/(36 pi) cm/min
2/(18 pi) cm/min
4/(9 pi) cm/min
7/(24 pi) cm/min

anonymous · Answer

I would determine the initial volume of the sphere.

anonymous · Answer

In this case, I believe the formula is (4pi (r)3)3, but Ime not sure

anonymous · Answer

wiki says its (4/3)*(pi)*r^3. Lets try it out. $$\left(\begin{matrix}4 \ 3\end{matrix}\right)\Pi r ^{3} $$ $$\left(\begin{matrix}4 \ 3\end{matrix}\right)\Pi 30 ^{3}  =3770 cm ^{3}$$

anonymous · Answer

wut, I am not getting the same results. 1 sec

anonymous · Answer

actually, I am afraid I dont know! Someone help please!

anonymous · Answer

But I guess, try to find the relation between the radius's rate of change and the rate of change of the sphere getting bigger. Ill be back