A 747 airliner reaches its takeoff speed of 179 mi/h in 33.7 s. What is the magnitude of its average acceleration?

I need step by step, some how im getting the wrong answer :(

Question

A 747 airliner reaches its takeoff speed of 179 mi/h in 33.7 s. What is the magnitude of its average acceleration?

I need step by step, some how im getting the wrong answer :(

anonymous · Answer

mi/h WTF? But yeah.. americans and units xD

Anyhow: If I am not mistaken 179 mph are equal to approx. 80.02 m/s$$(a)ccelaration = {(v)elocity \over (t)ime}$$$$a = {v \over t} = {80.02{m \over s} \over 33.7s} \approx 2.37 {m \over s^2}$$

anonymous · Answer

Wow, I wasn't getting the right answer because I didn't realize I had to convert to m/s^2. Thanks.