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r=30000p-2000p^2 how do calculate the maximum revenue using calculus ??
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Use x = -b/2a
b = 30000 a = -2000
15000
But we have to find y
\[ r \prime = 30000 -4000 p\]
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I mean, r, not y, lol
30000-4000 p =0 ===>p = 7.5 ===r(7.5) = 112500
sorry p = 7.5
r = 112,500 as raheen stated
yes but how do you guys get 112500 i can only get it to equal 0
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There's two ways to find it...Either use p = -b/2a or take the derivative, set it equal to zero and solve for p. I recommend using p = -b/2a. It's easier
thanks
since the calculus metheod was required, one must solve by derivative method
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