Evaluate each expression.
Evaluate each expression. \[Sin\frac{5\pi}{3}\]
sin((`)/(3)) Take the sine of (`)/(3) to get (~(3))/(2). (~(3))/(2) ~ means square root ' means pi
and similarly
sin((5`)/(3)) Take the sine of (5`)/(3) to get -(~(3))/(2). -(~(3))/(2)
sin((5`)/(3)) To find whether the value of sin((5`)/(3)) is negative or positive, setup a triangle that represents the unit circle based on the definition of sin. T[,90,(5`)/(3),-(~(3))/(2),(1)/(2),1,,,] Find the value using the definition sin((5`)/(3))=(opp)/(hyp). sin((5`)/(3))=(opp)/(hyp)=(-(~(3))/(2))/((1)/(2)) To divide by (1)/(2), multiply by the reciprocal of the fraction. sin((5`)/(3))=(opp)/(hyp)=2*-(~(3))/(2) Remove the common factor of 2 from the numerator of the first expression and denominator of the second expression. sin((5`)/(3))=(opp)/(hyp)=-~(3)
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