Question

solve for
\[\left( \sqrt{5x}-3\right)^{2}\]

Answer 1

You can't solve that unless it equals something

Answer 2

You can

Answer 3

I guess you can expand it and then try solving for x

Answer 4

\[(\sqrt{5x}-3)(\sqrt{5x}-3)\]Solve.

Answer 5

well i think you mean to make it a polynomial in which case it would be
\[(\sqrt5x-3)(\sqrt5x-3)\]\[5x-3\sqrt5-3\sqrt5+9\]\[5x -6\sqrt5 +9\]

Answer 6

^ yep, that's where I was going too

Answer 7

but there is nothing to solve for so you can't solve for x

Answer 8

Agreeeeeee.

Answer 9

\[9-6 \sqrt{5} \sqrt{x}+5 x\]

Answer 10

if it was 5x-6(sqrt5) +9 = 0 you could

Answer 11

\[-6 \sqrt{5} \sqrt{x}+5 x=-9\]

x=5/9

Answer 12

but that wasn't part of the problem, imran. you can't do that.

Answer 13

its a problem not an equation. there is no other side that you can subtract the 9 to.