Question

A geosyncchronous equatorial orbiting (GEO) satellite orbits 22.300 miles above the equator of Earth. It completes one full revolution each 24 hours. Assume Earth's radius is 3960 miles.

Answer 1

Let me try......ok, I can assume that :)

Answer 2

Done, I have assumed that the Earth's radius is 3960 miles. Now what?

Answer 3

a) How far will the GEO satellite travel in one day ?

Answer 4

b) Whay is the satellite's linear velocity in miles per hour ?

Answer 5

Then it travels in a circle with radius 3960+22.3 miles in a day so 2πr with r=3988.3.

Answer 6

For part a. about 25,046.524 miles

Answer 7

For part b. just divide by 24 and you get 1043.60517 miles per hour.

Answer 8

a) 1 day = 3960+ 22.982.3 than ?

Answer 9

3960 + 22.982.3 represents the outer radius because satellite orbits above equator of the earth

Answer 10

The to solve for how far it will travel in one day (24 hours) you use the circumference formula: 2*pi*r...r = 3988.3

Answer 11

So 2*(pi)*(3988.3) = 25,046.524 miles

Answer 12

Then linear velocity in miles per hour is 25,046.525 miles/ 24 hours = 1043.6052 miles / hour

Answer 13

radius small circle = 3960
big circle= 33.300?

Answer 14

no radius of big circle is 3960 + 33.300 = 3993

Answer 15

Think about it you start from center of inside circle

Answer 16

than small is ?

Answer 17

small is what you were given to start with: 3960

Answer 18

full revolution each 24 hours, for travel big circle ?

Answer 19

Good full revolution of 24 hours is 2*pi*r
pi is constant = 3.14..or use your calculator for approximation
r = 3993

Answer 20

Do you get it?

Answer 21

22.300+3960=26.260

Answer 22

26.260^2*3.14?

Answer 23

I don't know how u get 3993?