identify discontinuities-state whether they are removable or finite.
f(x)=(3x-2)/(x^2-3x-4)
f(x)=1/(x-1)

Question

anonymous · Answer

for both functions, solve the denominator for 0 to find where it is discontinuous:
$$x^{2} - 3x - 4 = (x - 4)(x + 1)$$
for the denominator to equal 0, x can be 4 or -1

For the 2nd, function it would be x=1

anonymous · Answer

oh, and none of them are removable as far as I can tell

anonymous · Answer

thanks!!

anonymous · Answer

If the factor that produced the root in the denominator is cancelled out when reducing to lowest terms, then the discontinuity is removable.  Neither of these are.