I have been stuck on this for hours PLEASE ANYONE the length of each side of a square is 3 inches more than the length of each side of a smaller square. The sum of the areas of the squares is 149square inches.Find the lengths of the sides of the two squares.

Question

I have been stuck on this for hours PLEASE ANYONE  the length of each side of a square is 3 inches more than the length of each side of a smaller square. The sum of the areas of the squares is 149square inches.Find the lengths of the sides of the two squares.

anonymous · Answer

Let x be the length of the side of the small square. The large square has length x+3.
x^2 + (x+3)^2 = 149

anonymous · Answer

yes

anonymous · Answer

x^2+x^2+6x+9=149
2x^2+6x=140
x^2+3x=70
x^2+3x-70=0

anonymous · Answer

(x+10)(x-7)=0 
so x = -10, 7

anonymous · Answer

It can't be -10 (as the length can't be negative) so the lengths must be 7 and 10

anonymous · Answer

Solving the last one you get$$(x+10)(x-7)=0$$ or $$x=7$$ for the smaller side

anonymous · Answer

thank you not sure where i went wrong