1/y-4 + 1/6 =-4/3y-12
this is fractions
Yes, I know
can you help me you think?
Yes, but you're going to have to learn how to post fractions if you want proper help
how do i post fractions?
Well, if you're going to post the linear form, you have to use parentheses to separate the numerator from the denominator
use my equation as a example so i know?
For example: (1)/(y-4) + (1)/(6) = (-4)/(3y-12)
I know it may seem like a lot, but it helps avoid confusion later
Thank you
\[\frac{1}{y-4} + \frac{1}{6} = \frac{-4}{3y-12}\] This is done by typing "\frac{1}{y-4} + \frac{1}{6} = \frac{-4}{3y-12}" without the quotes in the box that pops up when you click "Equation"
sometimes people just post them like this: 1/(y - 4) + 1/6 = -4/(3y-12) and sometimes that's good enough
Or you can do what alexray just demonstrated to be even clearer
Actually, if you use the equation editor you can simply type frac{1}{y - 4} + frac{1}{6} = frac{-4}{3y-12} and avoid all of the extra detail
Join our real-time social learning platform and learn together with your friends!