4z^2+5z-6
3+2 would be the five
4*-6=-24 Now we want factors of -24 that add up to 5: -3*8=-24 and -3+8=5
Now use the -3 and the 8 as coefficient for the 5x: \[4z^2-3z+8x-6\]
4x^2+8x-3x-6, 4x(x+2) -3(x+2) so (4x-3)(x+2)
The first two terms have a GCF of z, and the second two terms have a GCF of 2: \[z(4z-3)+2(4z-3)\]
4z^2+5z-6 , (4z- 3)(z+ 2)
Notice now that there are two terms each with the binomial 4z-3. Treat that binomial as a GCF (as if it is just a single letter or number) and factor it out: \[(4z-3)(z+2)\] This is your factored form.
good
Imagine A in place of the binomial in the second to last step: \[z(4z-3)+2(4z-3)\] zA+2A How would you factor this? Your factor out the A as a GCF! \[A(z+2)\] You are just doing that same thing with the 4z-3
im so dumb i gotta do these over and over again to figure it out lol thanks
Keep practicing!
And have fun while you are doing it :)
hahah i try
Join our real-time social learning platform and learn together with your friends!