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Mathematics 23 Online
OpenStudy (anonymous):

4z^2+5z-6

OpenStudy (anonymous):

3+2 would be the five

OpenStudy (anonymous):

4*-6=-24 Now we want factors of -24 that add up to 5: -3*8=-24 and -3+8=5

OpenStudy (anonymous):

Now use the -3 and the 8 as coefficient for the 5x: \[4z^2-3z+8x-6\]

OpenStudy (anonymous):

4x^2+8x-3x-6, 4x(x+2) -3(x+2) so (4x-3)(x+2)

OpenStudy (anonymous):

The first two terms have a GCF of z, and the second two terms have a GCF of 2: \[z(4z-3)+2(4z-3)\]

OpenStudy (anonymous):

4z^2+5z-6 , (4z- 3)(z+ 2)

OpenStudy (anonymous):

Notice now that there are two terms each with the binomial 4z-3. Treat that binomial as a GCF (as if it is just a single letter or number) and factor it out: \[(4z-3)(z+2)\] This is your factored form.

OpenStudy (nilankshi):

good

OpenStudy (anonymous):

Imagine A in place of the binomial in the second to last step: \[z(4z-3)+2(4z-3)\] zA+2A How would you factor this? Your factor out the A as a GCF! \[A(z+2)\] You are just doing that same thing with the 4z-3

OpenStudy (anonymous):

im so dumb i gotta do these over and over again to figure it out lol thanks

OpenStudy (anonymous):

Keep practicing!

OpenStudy (anonymous):

And have fun while you are doing it :)

OpenStudy (anonymous):

hahah i try

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