Question

4z^2+5z-6

Answer 1

3+2 would be the five

Answer 2

4*-6=-24
Now we want factors of -24 that add up to 5:
-3*8=-24
and
-3+8=5

Answer 3

Now use the -3 and the 8 as coefficient for the 5x:
\[4z^2-3z+8x-6\]

Answer 4

4x^2+8x-3x-6, 4x(x+2) -3(x+2) so (4x-3)(x+2)

Answer 5

The first two terms have a GCF of z, and the second two terms have a GCF of 2:
\[z(4z-3)+2(4z-3)\]

Answer 6

4z^2+5z-6 , (4z- 3)(z+ 2)

Answer 7

Notice now that there are two terms each with the binomial 4z-3. Treat that binomial as a GCF (as if it is just a single letter or number) and factor it out:
\[(4z-3)(z+2)\] This is your factored form.

Answer 8

good

Answer 9

Imagine A in place of the binomial in the second to last step:
\[z(4z-3)+2(4z-3)\]
zA+2A How would you factor this? Your factor out the A as a GCF!
\[A(z+2)\] You are just doing that same thing with the 4z-3

Answer 10

im so dumb i gotta do these over and over again to figure it out lol thanks

Answer 11

Keep practicing!

Answer 12

And have fun while you are doing it :)

Answer 13

hahah i try