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Physics 7 Online
OpenStudy (anonymous):

a mass of ikg is attached to a spring produce an extension of 0.1cm. its spring constant is 100N/m 10N/m 1000N/m 1N/m

OpenStudy (anonymous):

f=-kx f=kx k=f/x k=(1*10)/(0.1*10^-2)= 10,000 N/m but this choice is not availble

OpenStudy (anonymous):

IS it 1 kg?

OpenStudy (anonymous):

no its answer is 100

OpenStudy (anonymous):

From which book are you asking this question? and secondly which combination are you studying in F.Sc.

OpenStudy (anonymous):

first year book of fsc

OpenStudy (anonymous):

which page?

OpenStudy (anonymous):

are you premed or pre-engr?

OpenStudy (anonymous):

i m prepare entry test this question is book kips

OpenStudy (anonymous):

i m premed

OpenStudy (anonymous):

i get it .......you are on the chapter from oscillations?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

the mass is 1 kg..... g=10m/s^2......so the external force acting on the spring is 10 newton

OpenStudy (anonymous):

the extention in the string is 0.1cm=0.1*10^-2

OpenStudy (anonymous):

divide the first by the second what do you get in N/m?

OpenStudy (anonymous):

10/(0.1*10-2) = 10*100*10=10000 N/m definitely......unofficial entry test book not issued by testing authority can have lots of errors....

OpenStudy (anonymous):

f=mg=kx 0.1cm=.001m 1kg*10m/s^2=k*0.001m 10N/.001m=10000N/m

OpenStudy (anonymous):

The above options are incorrect because. 1kg*10m^s2=! 1000N/m*.001m or 100N/m *.001m and etc

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