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OpenStudy (anonymous):
a mass of ikg is attached to a spring produce an extension of 0.1cm. its spring constant is
100N/m
10N/m
1000N/m
1N/m
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OpenStudy (anonymous):
f=-kx
f=kx
k=f/x
k=(1*10)/(0.1*10^-2)= 10,000 N/m
but this choice is not availble
OpenStudy (anonymous):
IS it 1 kg?
OpenStudy (anonymous):
no its answer is 100
OpenStudy (anonymous):
From which book are you asking this question? and secondly which combination are you studying in F.Sc.
OpenStudy (anonymous):
first year book of fsc
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OpenStudy (anonymous):
which page?
OpenStudy (anonymous):
are you premed or pre-engr?
OpenStudy (anonymous):
i m prepare entry test
this question is book kips
OpenStudy (anonymous):
i m premed
OpenStudy (anonymous):
i get it .......you are on the chapter from oscillations?
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OpenStudy (anonymous):
yes
OpenStudy (anonymous):
the mass is 1 kg..... g=10m/s^2......so the external force acting on the spring is 10 newton
OpenStudy (anonymous):
the extention in the string is 0.1cm=0.1*10^-2
OpenStudy (anonymous):
divide the first by the second what do you get in N/m?
OpenStudy (anonymous):
10/(0.1*10-2) = 10*100*10=10000 N/m definitely......unofficial entry test book not issued by testing authority can have lots of errors....
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OpenStudy (anonymous):
f=mg=kx
0.1cm=.001m
1kg*10m/s^2=k*0.001m
10N/.001m=10000N/m
OpenStudy (anonymous):
The above options are incorrect because.
1kg*10m^s2=! 1000N/m*.001m or 100N/m *.001m and etc
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