Question

Find a point on the graph of y=4x whose distance to the origin is 2.

Answer 1

What does it mean by origin?

Answer 2

The point (0,0)

Answer 3

so how would I set this up to solve?

Answer 4

\[\sqrt{(x^2+y^2)}=2;y=4x\]

Answer 5

\[x^2+(4x)^2=4;\]

Answer 6

so then I would have \[x ^{2}+16x-4=0 \] and then use quadratic?

Answer 7

Yes

Answer 8

that can't be right b/c I have 2 x^2 then

Answer 9

so is it \[17x ^{2}-4\]

Answer 10

\[17x^2=4; x=\pm2/\sqrt17\]

Answer 11

Do the calculation cautiously.

Answer 12

My answers choices are (1,1) \[(2\sqrt{17}/17, 8\sqrt{17/17})\], none of the above , and (2,0). I went with none of the above. Is this right?

Answer 13

I feel it is because none of the other numbers matched.

Answer 14

Check you problem and see whether it is right.

Answer 15

I did I was just asking your opinion.

Answer 16

I already turned it it.

Answer 17

\[\frac{2}{\sqrt{17}}=\frac{2\sqrt{17}}{17}\]

Answer 18

and four times that is
\[\frac{8\sqrt{17}}{17}\] so that answer would be correct