Question

solve sec theta-cosec theta=4/3

Answer 1

help

Answer 2

I wish I was more familiar with secant and cosecant, try putting this into wolframalpha

Answer 3

http://www.wolframalpha.com/input/?i=sec+theta-cosec+theta%3D4%2F3

Answer 4

\[Sec \theta - cosec \theta = 4/3\] correct.....

Answer 5

helpppppppppp

Answer 6

AEQEL HELP

Answer 7

Secant and Cosecant are the inverse of the trignometric functions.
So, [sin(Theta)]^-1 - [cosine(Theta)]^-1 = 4/3
Inverse both sides you get:
sin(theta) - cos(theta) = 3/4

I think..

Answer 8

SO???

Answer 9

Do you wish to solve for theta?

Answer 10

ya

Answer 11

I'm sure there's a trig identity for this... Let me check my notes.

Answer 12

:)

Answer 13

U GUD AT trigonometry??

Answer 14

lol who knows?

Answer 15

I can't find my books! ><

Answer 16

oops

Answer 17

I did this like 2 years ago..

Answer 18

thn here is another one

Answer 19

ax/cos theta)+(by/sin theta)=a^2-b^2 and (axsin theta/cos^2 theta)-(bycos theta/sin^2 theta)=0
show that (ax)^2/3 +(by)^2/3=(a^2-b^2)^2/3

Answer 20

apparently the correct answer is
\[2\pi-\tan^{-1}(2-\sqrt{7})\]or
\[2\pi-\tan^{-1}(2+\sqrt{7})\]

Answer 21

how???

Answer 22

these problems are for the birds

Answer 23

how u got it?/?

Answer 24

where do they come from?

Answer 25

aeqel help plzz

Answer 26

:)

Answer 27

yeah i think i got it

Answer 28

wow

Answer 29

tl plzzzzz

Answer 30

.........

Answer 31

....................................

Answer 32

Okay so you know that sin(theta) = cos(theta-pi/2)
Replace one of the sin with that then solve.

Answer 33

wt abt second question?

Answer 34

btw there's another trig idenity that you need... let me find it.

Answer 35

sin(2theta) = 2sin(theta)cos(theta)
and
cos(2theta)=cos^2(theta)-sin^2(theta)

Answer 36

thn???

Answer 37

Wouldn't have a clu with the other question...

Answer 38

:) anothr one thn

Answer 39

solve tan theta+tan 2 theta+tan 3 theta =0

Answer 40

tan^2 theta ?

Answer 41

or is that tan(2theta) ?

Answer 42

tan(2theta)

Answer 43

okay, hmmm...

Answer 44

.................

Answer 45

I suppose you could use the trivial solution and that is when sin(theta) = 0 and cos(theta) = 0 ..

Answer 46

sorry costheta = 1

Answer 47

?

Answer 48

Well tan = sin/cos ...
So if sin = 0, sin/cos = 0

Answer 49

i.e. the Answer is theta = 0, x*pi where x is an integer

Answer 50

0 or x*pi that is.

Answer 51

:)

Answer 52

That one is conceptual.

Answer 53

i have a solution

Answer 54

?

Answer 55

to the first problem

\[\sec(\theta)-\csc(\theta)=\frac{4}{3}\]

Answer 56

actually there is something wrong with my solution, let me see if i can fix it