Question

Is this possible: An object has an initial speed of 15 m/s. How must it accelerate at a constant rate of 3 m/s^2 before its average speed its equal to twice its initial speed?

Answer 1

\[v = v_{0} + at \]
Then we know that double of the inicial velocity is 30 m/s.
Hence, this pretty easy:
\[30 = 15 + 3t <=> t = 5 s

Answer 2

the average speed not average velocity
\[v _{av }=d/t\]

Answer 3

Americas equation holds for velocity and speed if the object is moving in a staraight line - and the acceleration is constant.

Answer 4

5 sces is the correct answer