okay no i have a question ;D it's the write the equation for a piece wise fucntion junk, but i don't get this one.....?.....................
i will upload a picture ...
\[f(x) = |x+4| = \left\{\begin{array}{rcc} x + 4 & \text{if} & x \geq -4 \\ - x - 4& \text{if} & x < -4 \end{array} \right. \] just showing off
haha very funny
sorry, couldn't resist. i will be quiet and wait for the picture
okay it's Number 38 ! LOL, btw satellite.....ur old ,jk help?
old? you have no idea!
sorry it's side ways
so we three 3 different linear equations
so lets work on the first one
i will do #38
okay :D
we see that (-2,4) and (-4,-2) lie on the first line
we can find the slope and the y-intercept using \[m=\frac{y_1-y_2}{x_1-x_2}=\frac{4-(-2)}{-2-(-4)}=\frac{6}{2}=3\] \[y-y_1=m(x-x_1)\] \[y-4=3(x-(-2))\] \[y=3x+6+4=>y=3x+10\] so this line y=3x+10 is defined (-inf,2]
now the second line is a constant which is y=4 it is defined on (-2,2)
three lines. they change at -1 and 1 between -1 and 1 the function is constant. it is 2 before -1 it is a line with slope 3 (over 1, up 3) and since it goes up to (-1,2) the equation is \[y-2=3(x-1)\] or \[y=3x+5\] so we know it will look like \[f(x) = \left\{\begin{array}{rcc} 3x + 4 & \text{if} & x \leq -1 \\ 2& \text{if} & -1<x < 1\\ \text{something}& \text{if} & x>1 \end{array} \right. \]
now last line
opps sorry for the picture flip, but it sounds right
we see (2,4) and (4,-2) is on the line \[m=\frac{y_2-y_1}{x_2-x_1}=\frac{4-(-2)}{2-4}=\frac{6}{-2}=-3\] \[y-y_1=m(x-x_1)\] \[y-(-2)=-3(x-4)\] \[y+2=-3x+12\] \[y=-3x+10\] defined on [2,inf)
so this line y=3x+10 is defined (-inf,2] <------ how do u know it is closed circle?
they match up there so it makes no difference
you can do it either way it doesn't matter
OHHH
you can include for the constant line instead
still i am wrong!!!!!!!!!!!!!!!!!!!
\[f(x) = \left\{\begin{array}{rcc} 3x + 10 & \text{if} & x \leq -2 \\ 4 & \text{if} & -2<x < 2\\ -3x+10& \text{if} & x\geq 2 \end{array} \right.\]
lol satellite
why do they have to count by 2's?
lol satellite is to eager to help so he/she keeps messing up
i am going to go delete all my wrong posts.
my excuse it i had to read it sideways. that, and i am old...
lol maybe you should retire
satellite is awesome don't make him retire
yeah it is time. after labor day for sure
don't leave me satellite
it's just an option, you really dont have to if you don't want to
actually i just wanted to show off my piecewise function.
LOL, i wish i was smart,so i would actually have the ability to show off
BTW ty all
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