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I am in need of help again. (t/8)-(8/t)
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\[\frac{t}{8}-\frac{8}{t} = \frac{t}{8} \times \frac{t}{t} -\frac{8}{t} \times \frac{8}{8}\]\[= \frac{t^2-64}{8t}\]
oh and the equation =0 if that makes a difference. I really hate math lol
|dw:1315169431934:dw|
u mean \[\frac{t^2-64}{8t} =0\]\[=> t^2-64=0 => (t-8)(t+8) =0\]
(t/8)-(8/t)=0
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yea the equation i wrote is the same as the one u hav,
but i used a common denominator
so would the answer be 8 and -8 since it is set to 0? or would it be the simplified fraction?
yess 8 and-8
great, thank you for all your help! Glad I found this site today!
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your welcome=)
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