Question

|1/3x+4|>1

Answer 1

I don't understand the expression in the abs value

Answer 2

pretend as if the absolute value isn't there and the inequality isn't there
it will look more like this:
1/3x+4=1

Answer 3

would I switch the > sign to a < when i change the 1 to a -1?

Answer 4

1/3x+4=1

subtract 4 from both sides

1/3x = -3
divide both sides by 1/3

(yes you would)

Answer 5

Im getting there !

Answer 6

\[\frac{1}{3}x+4>1\] or
\[\frac{1}{3}x+4<-1\] and you are gong to have to solve these separately
oh ok i will be quiet, sorry

Answer 7

multiply both sides by the reciprocal
1/3*3/1 = -3 (3)
x= -9
now hold on to that and do the other side

Answer 8

which is -1/3x-4= 1 (the one does not change because it is not in the abs value lines)

Add 4 to both sides
-1/3x=5

next solve for x by doing the reciprocal

then it becomes -1/3 *3/1 = 5 *3
x=15

Answer 9

now put it all together:

Answer 10

and so

pretend as if the absolute value isn't there and the inequality isn't there
it will look more like this:
1/3x+4=1


1/3x+4=1

subtract 4 from both sides

1/3x = -3
divide both sides by 1/3


multiply both sides by the reciprocal
1/3*3/1 = -3 (3)
x= -9

which is 1/3x+4= -1 (the one does not change because it is not in the abs value lines)

subtract 4 to both sides
1/3x=-5

next solve for x by doing the reciprocal

then it becomes 1/3 *3/1 = 5 *3
x=-15
now put it all together:
-9> x
and/or
-15< x

i think that's it