Question

log(2)(x+4)+log(2)(x-2)=4
x=___?
I got 1 as my answer, right??

Answer 1

no!

Answer 2

6?

Answer 3

lol, i suck at this....still

Answer 4

satellite i need your help

Answer 5

x cannot be 1 because you have
\[\log_2(x-2)\]

Answer 6

when you are done

Answer 7

and 1-2=-1 and you cannot take the log of a negative number

Answer 8

ok hold on lets finish this one

Answer 9

you get
\[log_2((x+4)(x-2))=4\]
\[(x+4)(x-2)=2^4=16\]

Answer 10

16???? I was waaaaay off!!!!

Answer 11

not done yet!

Answer 12

ok, I need to find x.. ok

Answer 13

\[x^2+2x-8=16\]
\[x^2-2x-24=0\]
\[(x+6)(x-4)=0\]
\[x=4\]

Answer 14

ignore -6

Answer 15

thnx, u rock

Answer 16

yw