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(x)/(x+4)-(4)/(x-4)=(x^2+16)/(x^2-16)
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let me rewrite for clarity
\[\frac{x}{(x+4)}-\frac{4}{(x-4)}=\frac{(x^2+16)}{(x^2-16)}\]
Do you know what's special about x^2-16?
DIFFERENCE OF TWO PERFECT SQUARES
So that becomes (x+4)(x-4)
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Now say that we wanted to get rid of the denominators so this problem is easier. We can multiply the whole equation by (x+4)(x-4), because that takes care of all the denomointors
it becomes...
\[x(x-4)-4(x+4)=x^2+16\]
Do you see how I got that?
@slaven? :P
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