Question

the 3 should be on top of the sqrt

Answer 1

can you draw it out

Answer 2

wouldnt the answer be 3-x?

Answer 3

It's not much simpler, but you could rewrite this as
\[\sqrt[3]{81x}-\sqrt[3]{3x^{4}}= 3\cdot \sqrt[3]{3x}-x\cdot \sqrt[3]{3x}\]
\[= (3-x) \cdot \sqrt[3]{3x}\]

Answer 4

ohh theres more to the problem? well the begging is 3-x i agree.

Answer 5

beggining**

Answer 6

it would be (3-x)(3-x), which is x^2-6x+9.....