How do you know that a Quadratic equation cannot be solved by factoring, but can be solved by using the quadratic formula?
If the discriminant isn't a perfect square, then you cannot solve the equation by factoring.
well really any quadratic equation can be solved by factoring or by quadratic formula
oh I meant factoring over the rationals
i have proved this
although it is hard to factor over the complex it is not impossible
Usually I try by factoring method if it fails then I resort to quadratic formula which works for ANY quadratic equation.
by "factor" I think they mean do so without the quadratic formula (ie find two numbers that multiply to this and add to that...etc)
usually people just try to factor over the integers then if that is not possible they result to the quadratic formula (or completing the square)
i can factor without the quadratic formula
lol well average people then
give me any quadratic and i will show you
For instance: x^2 + 3x + 5 this is not factorable so you have to use the quadratic formula and you will get a complex root.
not superhuman machines lol
lol
\[\left(x-\frac{-3}{2}-\frac{\sqrt{11}}{2}i\right)\left(x-\frac{-3}{2}+\frac{\sqrt{11}}{2}i\right)\]
we can use factor by grouping as i did in this file above
0.0 wow
cool!!...learnt something new today
i come up with that way
:)
i made a proof for the quadratic formula
but its run time is much longer than completing the square
so it almost useless
thank you for all the help ^.^
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