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The side lengths of a square (L) are increasing at a constant rate of 2 cm/min. If the area of a square is A. Then dA/dL is equal to?
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A= L^2 ===> dA/dL= 2L *dL/dt === > 2L *2 = 4L
the answer is 2L
oh yeah its right sorry lol i didn't see your s da/dl
ok , great
it depends on the law of area
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so the area of a square is L x B so thats why its L^2
since B = L in the square, it's better to write the area in this form A=L*L =L^2
i see thank you very much :)
yoy are welcome
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