Question

3.3!+4.4!+5.5! .......19.19! divided by 64 leaves a remainder ?

Answer 1

anyone attempting ?

Answer 2

3.3!=4!-3!
4.4!=5!-4!
proceeding this way u can get, 20!-19!+19!-18!+18!-17!+.........-3!=20!-3!
20! is divisible by 64.
3!=6 so the remainder will be 58

Answer 3

is it correct?

Answer 4

your notation is not good.

if you wanted 3 times 3 factorial then you should use

\[3*3!\text{ or }3\times3!\text{ or }3\cdot3! \]

when you use a period then you get this

\[3.3!=(3.3)!=\Gamma[3.3+1]\approx8.85534336046\]

\[\text{where }\Gamma[\cdot]\text{ is the gamma function}\]

Answer 5

if it is multiplication then Arnab09 is correct

Answer 6

whats wrong with my answer?

Answer 7

actually, i solved it taking it as a multiplication sign

Answer 8

nothing..I said you are correct...provided the period used represents multiplication.