Question

how do i solve this equation? x^2-16x+48=0

Answer 1

(x-12)(x-4)=0 ===> x=12 or x=4

Answer 2

factorise it as done by raheen

Answer 3

so is it basically raheen, its like the previous problems we were doing?

Answer 4

exactly.

Answer 5

im stuck at x(2x+7)(3x-1)=0

Answer 6

how do i get it back the other way?

Answer 7

multiply the brackets first then mutiply x in the product

Answer 8

You can use the quadratic formula
\[x= (-b ± \sqrt{b^2-4ac})/2a\]
In this case, you can do something like

\[x^2-16x+48=0\]
\[x= (-(-16) ± \sqrt{(-16)^2-4(1)(48)})/2(1)\]
\[x=(16±\sqrt{64})/2\]
\[x=8±4\]
\[\lfloor x=12 \rfloor\ OR \lfloor x=4 \rfloor\]