Question

solve the nonlinear inequality: 3\(x-1) - 4\x > or = 1

Answer 1

'\' mean division,right?

Answer 2

yes

Answer 3

okay first take L.C.M it will give you [3x-4(x-1)]/x(x-1)>=1 then it will give you by simplification : (1-x)>=x^2-x this implies 1>=x^2 take under rrot on both sides you will get x<=1

Answer 4

can you show the steps of simplification please
?

Answer 5

(3/x-1)-(4/x)>=1
[3(x)-4(x-1)/x(x-)]>=1 (L.C.M)
[1-x/x(x-1)]>=1
1-x>=x(x-1) (Multiply both sides by x(x-) )
1-x>=x^2-x
1-x+(x)>=x^2-x+(x) (Adding x on both sides)
1>=x^2
taking sqrt on both sides
1>=x
this implies x<=1 OKAY NOW?

Answer 6

this answer does not appear to work when inserted in the equation

Answer 7

x must not be equal to 0 and 1 because they make this undefined.Everthing else works