find limit as x approaches pi/2 from negative side.

f(x)=(tanx)^[(pi/2)-x]

Question

find limit as x approaches pi/2 from negative side.

f(x)=(tanx)^[(pi/2)-x]

anonymous · Answer

$$\lim_{x \rightarrow \pi/2^{-}} tanx ^{(\pi/2)-x}$$, answer should be "1" but i need to know the step by step process

anonymous · Answer

f(x) = tanx ^ [(pi/2) - x]
f(x) = e^ [(pi/2 - x) x ln tanx ]
when x approaches pi/2,
then f(x) = e^0 = 1

anonymous · Answer

thank you jyouie :)

anonymous · Answer

Nope, what is your age now? This is something more advanced....

anonymous · Answer

actually i'm 20 and in college

anonymous · Answer

so are you saying thats not the answer? aha

anonymous · Answer

...I'm not quite sure, 'cause me too, I'm still studying at secondary school (something like high school in us)....18 ^^

anonymous · Answer

lol XD

anonymous · Answer

well it seems like you know a lot more than I do, you haven't even taken the advance course yet. i give you kudos.

anonymous · Answer

you know how to use l'hopital's rule?