Question

Rearrange this formula to make V the subject:
A= /sqrt[3]{a} 36V^2

Answer 1

\[A=\sqrt[3]{36V^2}\]?

Answer 2

type \sqrt[3]{36v^2}

Answer 3

/sqrt[3]{36v^2}

Answer 4

open with \[

Answer 5

end with \]

Answer 6

\[sqrt[3]{36V^2}\]

Answer 7

in any case cube both sides to get
\[A^3=36V^2\] then
\[V^2=\frac{A^3}{36}\] so \[V=\pm\frac{\sqrt{A^3}}{6}\]

Answer 8

getting closer
you forgot the \ before the sqrt

Answer 9

whats the plus with the underscore?

Answer 10

@isuckatmaths i can show you in chat
not here because it just renders the math

Answer 11

or you can right click on what i wrote, choose "show source" and you will see it

Answer 12

V^2=\frac{A^3}{36}

Answer 13

start with \[