Question

domain of x+3/4-sqrt(x^2-9)??? explain answer please

Answer 1

domain of a function is basically what values of x can be used in the function without computing an error or does not exist

Answer 2

domain is x is an element of the Reals, you have no restrictions

Answer 3

x cannot be 0 right because then it would be undefined

Answer 4

yes correct, because you cannot take the sqrt of a negative unless your using complex numbers to simplify

Answer 5

is this
\[f(x)=\frac{x+3}{4}-\sqrt{x^2-9}\]?

Answer 6

if so you have to make sure that
\[x^2-9\geq0\] meaning
\[x\leq -3\] or
\[x\geq 3\]

Answer 7

\[x+3/(4-\sqrt{x ^{2}-9})\]

Answer 8

ok let then in that case not only must you have
\[x\leq-3\] or
\[x\geq 3\] you also have to make sure that
\[\sqrt{x^2-9}\neq 4\] because you cannot divide by 0

Answer 9

this means
\[x^2-9\neq 16\] so
\[x^2\neq 25\] so
\[x\neq 5\]
\[x\neq -5\]