Question

hey, what is the horizontal asymptotes of 6x/x+1?

Answer 1

solve for x

Answer 2

lim(x...infinity, f(x))=7 ?

Answer 3

so the h.a is 7

Answer 4

im not sure if we could call it that, since y=6x/x +1 is y=7, i dont kow if the function itself is allowed to be its own asymp

Answer 5

okay thanks, so for this one x^6/x^2+7 would the h.a. be 1 and the vertical asymp be 7,-1

Answer 6

no, the lim f(x)x->infinity diverges
in general, if one has something like p(x)/q(x) the h.a only if q has a higher exponent than p

Answer 7

in other words, the limit must converge

Answer 8

thank you., i can still solve for my vertical asymptopes in the denominator tho right

Answer 9

in order to find vertical ones one search for the denominator= 0, but one must be careful that those answers are not also 0 in the numerator, those are not vertical asymptotes, they are "mathematical singularities"