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Limits as x goes to infinity.
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|dw:1315337161535:dw|
using lhospital is 1
1
how did you get that answer?
One x on top one x on bottom is 1. The 5 doesn't matter.
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consider a large number 100000000/(100000005)... seems obvious
No need for l'hopital's here.. \[\large \lim_{x\rightarrow\infty}\frac{x}{x-5} \]\[= \frac{\cancel{x}}{\cancel{x}(1-\frac{5}{x})}\]\[=\frac{1}{1-0} = 1\]
Whoops forgot the second limit there..
But in anycase.
\[1x/1\]
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When x approaches infinity \[\ \lim_{x \rightarrow +\infty} x/(x-5)\] is equal to \[\lim_{x \rightarrow +\infty} x/x=1\] Generally, when you're trying to figure out the limit of a polynomial, as x approaches infinity, then you consider only the x that is raised to the largest power.
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